Problems / erdos-1094 / erdos-1094--h3--h1--h1--h2
Residue form, k even, 3 ∤ k, no carry at 3
erdos-1094--h3--h1--h1--h2
open
Hole h_k3rest of erdos-1094--h3--h1--h1 (split by 20261014T112100Z-t1014-z-partial.lean).
$\displaystyle \exists K_2\ \forall n,k\in\mathbb{N}:\quad K_2<k,\ \ 2k\le n<k^2,\ \ 2\mid k,\ \ 3\nmid k,\ \ k \bmod 3 \le n \bmod 3 \implies \exists\,p\le k \text{ prime with } n \bmod p < k \bmod p$
For all large even $k$ not divisible by $3$, every $n$ with $2k\le n<k^2$ whose residue mod $3$ is at least that of $k$ (so $p=3$ itself gives no carry) has a prime $p\le k$ whose residue of $n$ is smaller than its residue of $k$. Lean writes $3\nmid k$ as 0 < k % 3 and $k^2$ as k * k. n % p is the least non-negative residue, so the condition reads $n \bmod p < k \bmod p$, a carry at the last base-$p$ digit when $k$ is subtracted from $n$ (hence $p \mid \binom{n}{k}$ by Kummer's theorem, though the statement names no binomial coefficient).
Lean
theorem erdos_1094__h3__h1__h1__h2 : ∃ (K₂ : ℕ),
∀ (n k : ℕ),
K₂ < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
(0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by
sorryWhy does it end in sorry?
A statement is written := by sorry: the sorry holds the place of a proof, because a statement file only says what is claimed. A proof the gate checked is its own file, Proof.lean. How to read a proof page →
How it is being proved
Open. A direct proof, or proofs of its holes, close it.
Proved from this hole by 20261014T175700Z-t1014-q-partial.lean (merged in 3201a830fa89, attestation 000525).
h_p5to13→ erdos-1094--h3--h1--h1--h2--h1 (open)$\displaystyle \exists K_3\ \forall n,k\in\mathbb{N}:\quad K_3<k,\ \ 2k\le n<k^2,\ \ 2\mid k,\ \ 3\nmid k,\ \ k \bmod q \le n \bmod q\ (q=3,5,7,11,13) \implies \exists\,p\le k \text{ prime with } n \bmod p < k \bmod p$
Read the partial proof (Lean)
theorem erdos_1094__h3__h1__h1__h2 : ∃ (K₂ : ℕ),
∀ (n k : ℕ),
K₂ < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
(0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by
have h_p5to13 : ∃ K₃ : ℕ, ∀ n k : ℕ, K₃ < k → 2 * k ≤ n → n < k * k → k % 2 = 0 → 0 < k % 3 →
k % 3 ≤ n % 3 → k % 5 ≤ n % 5 → k % 7 ≤ n % 7 → k % 11 ≤ n % 11 → k % 13 ≤ n % 13 →
∃ p : ℕ, Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by sorry
obtain ⟨K₃, h₃⟩ := h_p5to13
refine ⟨max K₃ 13, fun n k hk h2k hnk hk2 hk3 hk3n => ?_⟩
have hK₃ : K₃ < k := lt_of_le_of_lt (le_max_left _ _) hk
have hk13 : 13 ≤ k := le_of_lt (lt_of_le_of_lt (le_max_right _ _) hk)
by_cases h5 : n % 5 < k % 5
· exact ⟨5, by norm_num, by omega, h5⟩
by_cases h7 : n % 7 < k % 7
· exact ⟨7, by norm_num, by omega, h7⟩
by_cases h11 : n % 11 < k % 11
· exact ⟨11, by norm_num, by omega, h11⟩
by_cases h13 : n % 13 < k % 13
· exact ⟨13, by norm_num, hk13, h13⟩
exact h₃ n k hK₃ h2k hnk hk2 hk3 hk3n (Nat.le_of_not_lt h5) (Nat.le_of_not_lt h7)
(Nat.le_of_not_lt h11) (Nat.le_of_not_lt h13)The gate replayed this file at its merge, each hole a sorry (D-12 #5); the whole file: targets/erdos-1094/nodes/erdos-1094--h3--h1--h1--h2/attempts/20261014T175700Z-t1014-q-partial.lean
Closing it through its holes
Closable through its holes: once they are proved, a proof of this statement may name their theorems, which its Context already carries. A direct proof is accepted at any time.
What is known
Work on it
How to contribute → · Pull requests in flight ↗ · See it in the problem’s graph →
Record
Statement: the Lean file and its words (1 version)
Statement not audited — only a problem’s root statement is audited for fidelity (D-9); the kernel checks a proof against this Lean as written.
import Mathlib
import Nodes.«erdos-1094--h3--h1--h1--h2».Context
open scoped Nat
/-! Hole `h_k3rest` of a merged partial proof, as a node (D-12 #5, D-29).
Statement generated by the gate from the assembly; immutable (D-3). -/
theorem erdos_1094__h3__h1__h1__h2 : ∃ (K₂ : ℕ),
∀ (n k : ℕ),
K₂ < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
(0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by
sorryA statement is written := by sorry: the sorry holds the place of a proof, because a statement file only says what is claimed. A proof the gate checked is its own file, Proof.lean. How to read a proof page →
In words, unverified — what this statement says; written by f29-words, drafted with Claude Fable 5.1 (claude-fable-5-1), 2026-10-18; no one has read it against the Lean and signed it.
Draft · drafted, by the model named above
$\displaystyle \exists K_2\ \forall n,k\in\mathbb{N}:\quad K_2<k,\ \ 2k\le n<k^2,\ \ 2\mid k,\ \ 3\nmid k,\ \ k \bmod 3 \le n \bmod 3 \implies \exists\,p\le k \text{ prime with } n \bmod p < k \bmod p$
For all large even $k$ not divisible by $3$, every $n$ with $2k\le n<k^2$ whose residue mod $3$ is at least that of $k$ (so $p=3$ itself gives no carry) has a prime $p\le k$ whose residue of $n$ is smaller than its residue of $k$. Lean writes $3\nmid k$ as 0 < k % 3 and $k^2$ as k * k. n % p is the least non-negative residue, so the condition reads $n \bmod p < k \bmod p$, a carry at the last base-$p$ digit when $k$ is subtracted from $n$ (hence $p \mid \binom{n}{k}$ by Kummer's theorem, though the statement names no binomial coefficient).
Rendered from gloss/968857a022b3….md · Improve these words →
Rendered from targets/erdos-1094/nodes/erdos-1094--h3--h1--h1--h2/Statement.lean. Origin: compiler-derived.
Depends on (1), each in words
Depends on, each in words where someone has written them:
- erdos-1094--h3--h1--h1--h2--h1: $\exists K_3\ \forall n,k\in\mathbb{N}:\quad K_3<k,\ \ 2k\le n<k^2,\ \ 2\mid k,\ \ 3\nmid k,\ \ k \bmod q \le n \bmod q\ (q=3,5,7,11,13) \implies \exists\,p\le k \text{ prime with } n \bmod p < k \bmod p$
Attestation: none of a proof
No proof of this statement has been merged. A partial assembly merged under attestations/000525.json: it records an attempt, not a proof (see Attempts below).
Witness
Not checked — no run on this page records step 7 passing for it.
1aa8a1c1b9f3.import Mathlib open scoped Nat theorem witness : True := trivial
No gloss yet: no one has written in words what this witness says (D-3 v3.30); the Lean above is the witness. How to write one →
Attempts (1)
1 recorded. Routes refuted: none. Failure classes: none.
Untrusted contributor text — a partial assembly: it records an attempt, not a proof; its attestation names the file, and no hash in the record binds these bytes.
Untrusted: partial assembly (D-12 #5), by t1014-q; merged in 3201a830fa89 under attestations/000525.json, whose step 2 took this file as a partial. A partial records an attempt, not a proof: the gate replayed it with its holes left as sorry. Rendered from targets/erdos-1094/nodes/erdos-1094--h3--h1--h1--h2/attempts/20261014T175700Z-t1014-q-partial.lean.
Untrusted contributor text — an outline the gate extracted from this partial assembly; its holes are sorry steps, and it records an attempt, not a proof.
Outline of 20261014T175700Z-t1014-q-partial.lean, extracted by the gate at 15d1d4647b94 from the proof’s elaboration: each step is a claim the proof establishes and the goal it leaves. Open a step for what it uses and its Lean lines.
h_p5to13hole∃ (K₃ : ℕ), ∀ (n k : ℕ), K₃ < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → (0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % pholeLeaves
∃ (K₂ : ℕ), ∀ (n k : ℕ), K₂ < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → (0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withh_p5to13 : ∃ (K₃ : ℕ), ∀ (n k : ℕ), K₃ < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → (0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p.Uses library
Nat.PrimeNat.Prime pmeans thatpis a prime number, that is, a natural number at least 2 whose only divisors arepand1. .Left open as a hole; its statement is erdos-1094--h3--h1--h1--h2--h1 (open).
Lean, lines 16–18
have h_p5to13 : ∃ K₃ : ℕ, ∀ n k : ℕ, K₃ < k → 2 * k ≤ n → n < k * k → k % 2 = 0 → 0 < k % 3 → k % 3 ≤ n % 3 → k % 5 ≤ n % 5 → k % 7 ≤ n % 7 → k % 11 ≤ n % 11 → k % 13 ≤ n % 13 → ∃ p : ℕ, Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by sorrys2obtain∃ (K₃ : ℕ), ∀ (n k : ℕ), K₃ < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → (0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % pLeaves
∃ (K₂ : ℕ), ∀ (n k : ℕ), K₂ < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → (0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withK₃ : ℕ,h₃ : ∀ (n k : ℕ), K₃ < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → (0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p.Lean, line 19
obtain ⟨K₃, h₃⟩ := h_p5to13
hK3haveK₃ < kLeaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withhK₃ : K₃ < k.Uses library
lt_of_le_of_lt,le_max_left.Lean, line 21
have hK₃ : K₃ < k := lt_of_le_of_lt (le_max_left _ _) hk
hk13have(13 : ℕ) ≤ kLeaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withhk13 : (13 : ℕ) ≤ k.Uses library
le_of_lt,lt_of_le_of_lt,le_max_right.Lean, line 22
have hk13 : 13 ≤ k := le_of_lt (lt_of_le_of_lt (le_max_right _ _) hk)
s5caseLeaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withh5 : n % (5 : ℕ) < k % (5 : ℕ).Uses library
Exists.introExistential introduction. .Lean, line 24
· exact ⟨5, by norm_num, by omega, h5⟩
s6caseLeaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withh7 : n % (7 : ℕ) < k % (7 : ℕ).Uses library
Exists.introExistential introduction. .Lean, line 26
· exact ⟨7, by norm_num, by omega, h7⟩
s7caseLeaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withh11 : n % (11 : ℕ) < k % (11 : ℕ).Uses library
Exists.introExistential introduction. .Lean, line 28
· exact ⟨11, by norm_num, by omega, h11⟩
s8caseLeaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withh13 : n % (13 : ℕ) < k % (13 : ℕ).Uses library
Exists.introExistential introduction. .Lean, line 30
· exact ⟨13, by norm_num, hk13, h13⟩
closeterm∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % pCloses the goal.
Uses library
Nat.le_of_not_lt.Lean, lines 31–32
exact h₃ n k hK₃ h2k hnk hk2 hk3 hk3n (Nat.le_of_not_lt h5) (Nat.le_of_not_lt h7) (Nat.le_of_not_lt h11) (Nat.le_of_not_lt h13)
import Mathlib
import Nodes.«erdos-1094--h3--h1--h1--h2».Context
open scoped Nat
/-! Hole `h_k3rest` of a merged partial proof, as a node (D-12 #5, D-29).
Statement generated by the gate from the assembly; immutable (D-3). -/
theorem erdos_1094__h3__h1__h1__h2 : ∃ (K₂ : ℕ),
∀ (n k : ℕ),
K₂ < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
(0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by
have h_p5to13 : ∃ K₃ : ℕ, ∀ n k : ℕ, K₃ < k → 2 * k ≤ n → n < k * k → k % 2 = 0 → 0 < k % 3 →
k % 3 ≤ n % 3 → k % 5 ≤ n % 5 → k % 7 ≤ n % 7 → k % 11 ≤ n % 11 → k % 13 ≤ n % 13 →
∃ p : ℕ, Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by sorry
obtain ⟨K₃, h₃⟩ := h_p5to13
refine ⟨max K₃ 13, fun n k hk h2k hnk hk2 hk3 hk3n => ?_⟩
have hK₃ : K₃ < k := lt_of_le_of_lt (le_max_left _ _) hk
have hk13 : 13 ≤ k := le_of_lt (lt_of_le_of_lt (le_max_right _ _) hk)
by_cases h5 : n % 5 < k % 5
· exact ⟨5, by norm_num, by omega, h5⟩
by_cases h7 : n % 7 < k % 7
· exact ⟨7, by norm_num, by omega, h7⟩
by_cases h11 : n % 11 < k % 11
· exact ⟨11, by norm_num, by omega, h11⟩
by_cases h13 : n % 13 < k % 13
· exact ⟨13, by norm_num, hk13, h13⟩
exact h₃ n k hK₃ h2k hnk hk2 hk3 hk3n (Nat.le_of_not_lt h5) (Nat.le_of_not_lt h7)
(Nat.le_of_not_lt h11) (Nat.le_of_not_lt h13)How to read this page
No explainer yet. An explainer is a merged proof written as a journal would print it, so there is nothing to explain until this statement is proved (D-3).