Problems / erdos-1094 / erdos-1094--h3--h1--h1--h2--h1
Residue form, k even, 3 ∤ k, no carry at 3 to 13
erdos-1094--h3--h1--h1--h2--h1
open
Hole h_p5to13 of erdos-1094--h3--h1--h1--h2 (split by 20261014T175700Z-t1014-q-partial.lean).
$\displaystyle \exists K_3\ \forall n,k\in\mathbb{N}:\quad K_3<k,\ \ 2k\le n<k^2,\ \ 2\mid k,\ \ 3\nmid k,\ \ k \bmod q \le n \bmod q\ (q=3,5,7,11,13) \implies \exists\,p\le k \text{ prime with } n \bmod p < k \bmod p$
For all large even $k$ not divisible by $3$, every $n$ with $2k\le n<k^2$ whose residue mod $q$ is at least that of $k$ for each of $q=3,5,7,11,13$ (so none of those five primes gives a carry) has a prime $p\le k$ whose residue of $n$ is smaller than its residue of $k$. Lean writes $3\nmid k$ as 0 < k % 3, the five no-carry hypotheses as k % q ≤ n % q, and $k^2$ as k * k. n % p is the least non-negative residue, so the condition reads $n \bmod p < k \bmod p$, a carry at the last base-$p$ digit when $k$ is subtracted from $n$ (hence $p \mid \binom{n}{k}$ by Kummer's theorem, though the statement names no binomial coefficient).
Lean
theorem erdos_1094__h3__h1__h1__h2__h1 : ∃ (K₃ : ℕ),
∀ (n k : ℕ),
K₃ < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
(0 : ℕ) < k % (3 : ℕ) →
k % (3 : ℕ) ≤ n % (3 : ℕ) →
k % (5 : ℕ) ≤ n % (5 : ℕ) →
k % (7 : ℕ) ≤ n % (7 : ℕ) →
k % (11 : ℕ) ≤ n % (11 : ℕ) →
k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by
sorryWhy does it end in sorry?
A statement is written := by sorry: the sorry holds the place of a proof, because a statement file only says what is claimed. A proof the gate checked is its own file, Proof.lean. How to read a proof page →
How it is being proved
Open. A direct proof, or proofs of its holes, close it.
Proved from these holes by 20261015T145026Z-t1015c-a09-partial.lean (merged in 7a4aeb081a83, attestation 000544).
h_k3one→ erdos-1094--h3--h1--h1--h2--h1--h1 (open)$\displaystyle \exists K\ \forall n,k\in\mathbb{N}:\quad K<k,\ \ 2k\le n<k^2,\ \ 2\mid k,\ \ k\equiv 1 \pmod 3,\ \ 1\le n \bmod 3,\ \ k \bmod q \le n \bmod q\ (q=5,7,11,13) \implies \exists\,p\le k \text{ prime with } n \bmod p < k \bmod p$
h_k3two→ erdos-1094--h3--h1--h1--h2--h1--h2 (open)$\displaystyle \exists K\ \forall n,k\in\mathbb{N}:\quad K<k,\ \ 2k\le n<k^2,\ \ 2\mid k,\ \ k\equiv 2 \pmod 3,\ \ n\equiv 2 \pmod 3,\ \ k \bmod q \le n \bmod q\ (q=5,7,11,13) \implies \exists\,p\le k \text{ prime with } n \bmod p < k \bmod p$
Read the partial proof (Lean)
theorem erdos_1094__h3__h1__h1__h2__h1 : ∃ (K₃ : ℕ),
∀ (n k : ℕ),
K₃ < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
(0 : ℕ) < k % (3 : ℕ) →
k % (3 : ℕ) ≤ n % (3 : ℕ) →
k % (5 : ℕ) ≤ n % (5 : ℕ) →
k % (7 : ℕ) ≤ n % (7 : ℕ) →
k % (11 : ℕ) ≤ n % (11 : ℕ) →
k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by
have h_k3one : ∃ (K : ℕ),
∀ (n k : ℕ),
K < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
k % (3 : ℕ) = (1 : ℕ) →
(1 : ℕ) ≤ n % (3 : ℕ) →
k % (5 : ℕ) ≤ n % (5 : ℕ) →
k % (7 : ℕ) ≤ n % (7 : ℕ) →
k % (11 : ℕ) ≤ n % (11 : ℕ) →
k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := sorry
have h_k3two : ∃ (K : ℕ),
∀ (n k : ℕ),
K < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
k % (3 : ℕ) = (2 : ℕ) →
n % (3 : ℕ) = (2 : ℕ) →
k % (5 : ℕ) ≤ n % (5 : ℕ) →
k % (7 : ℕ) ≤ n % (7 : ℕ) →
k % (11 : ℕ) ≤ n % (11 : ℕ) →
k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := sorry
obtain ⟨A, hA⟩ := h_k3one
obtain ⟨B, hB⟩ := h_k3two
refine ⟨max A B, ?_⟩
intro n k hk h1 h2 h3 h4 h5 h6 h7 h8 h9
have hAk : A < k := lt_of_le_of_lt (le_max_left A B) hk
have hBk : B < k := lt_of_le_of_lt (le_max_right A B) hk
have hk3 : k % 3 < 3 := Nat.mod_lt _ (by norm_num)
have hn3 : n % 3 < 3 := Nat.mod_lt _ (by norm_num)
rcases (by omega : k % 3 = 1 ∨ k % 3 = 2) with h | h
· exact hA n k hAk h1 h2 h3 h (by omega) h6 h7 h8 h9
· exact hB n k hBk h1 h2 h3 h (by omega) h6 h7 h8 h9The gate replayed this file at its merge, each hole a sorry (D-12 #5); the whole file: targets/erdos-1094/nodes/erdos-1094--h3--h1--h1--h2--h1/attempts/20261015T145026Z-t1015c-a09-partial.lean
Closing it through its holes
Closable through its holes: once they are proved, a proof of this statement may name their theorems, which its Context already carries. A direct proof is accepted at any time.
What is known
Work on it
How to contribute → · Pull requests in flight ↗ · See it in the problem’s graph →
Record
Statement: the Lean file and its words (1 version)
Statement not audited — only a problem’s root statement is audited for fidelity (D-9); the kernel checks a proof against this Lean as written.
import Mathlib
import Nodes.«erdos-1094--h3--h1--h1--h2--h1».Context
open scoped Nat
/-! Hole `h_p5to13` of a merged partial proof, as a node (D-12 #5, D-29).
Statement generated by the gate from the assembly; immutable (D-3). -/
theorem erdos_1094__h3__h1__h1__h2__h1 : ∃ (K₃ : ℕ),
∀ (n k : ℕ),
K₃ < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
(0 : ℕ) < k % (3 : ℕ) →
k % (3 : ℕ) ≤ n % (3 : ℕ) →
k % (5 : ℕ) ≤ n % (5 : ℕ) →
k % (7 : ℕ) ≤ n % (7 : ℕ) →
k % (11 : ℕ) ≤ n % (11 : ℕ) →
k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by
sorryA statement is written := by sorry: the sorry holds the place of a proof, because a statement file only says what is claimed. A proof the gate checked is its own file, Proof.lean. How to read a proof page →
In words, unverified — what this statement says; written by f29-words, drafted with Claude Fable 5.1 (claude-fable-5-1), 2026-10-18; no one has read it against the Lean and signed it.
Draft · drafted, by the model named above
$\displaystyle \exists K_3\ \forall n,k\in\mathbb{N}:\quad K_3<k,\ \ 2k\le n<k^2,\ \ 2\mid k,\ \ 3\nmid k,\ \ k \bmod q \le n \bmod q\ (q=3,5,7,11,13) \implies \exists\,p\le k \text{ prime with } n \bmod p < k \bmod p$
For all large even $k$ not divisible by $3$, every $n$ with $2k\le n<k^2$ whose residue mod $q$ is at least that of $k$ for each of $q=3,5,7,11,13$ (so none of those five primes gives a carry) has a prime $p\le k$ whose residue of $n$ is smaller than its residue of $k$. Lean writes $3\nmid k$ as 0 < k % 3, the five no-carry hypotheses as k % q ≤ n % q, and $k^2$ as k * k. n % p is the least non-negative residue, so the condition reads $n \bmod p < k \bmod p$, a carry at the last base-$p$ digit when $k$ is subtracted from $n$ (hence $p \mid \binom{n}{k}$ by Kummer's theorem, though the statement names no binomial coefficient).
Rendered from gloss/04e5f8f14db1….md · Improve these words →
Rendered from targets/erdos-1094/nodes/erdos-1094--h3--h1--h1--h2--h1/Statement.lean. Origin: compiler-derived.
Depends on (2), each in words
Depends on, each in words where someone has written them:
- erdos-1094--h3--h1--h1--h2--h1--h1: $\exists K\ \forall n,k\in\mathbb{N}:\quad K<k,\ \ 2k\le n<k^2,\ \ 2\mid k,\ \ k\equiv 1 \pmod 3,\ \ 1\le n \bmod 3,\ \ k \bmod q \le n \bmod q\ (q=5,7,11,13) \implies \exists\,p\le k \text{ prime with } n \bmod p < k \bmod p$
- erdos-1094--h3--h1--h1--h2--h1--h2: $\exists K\ \forall n,k\in\mathbb{N}:\quad K<k,\ \ 2k\le n<k^2,\ \ 2\mid k,\ \ k\equiv 2 \pmod 3,\ \ n\equiv 2 \pmod 3,\ \ k \bmod q \le n \bmod q\ (q=5,7,11,13) \implies \exists\,p\le k \text{ prime with } n \bmod p < k \bmod p$
Attestation: none of a proof
No proof of this statement has been merged. A partial assembly merged under attestations/000544.json: it records an attempt, not a proof (see Attempts below).
Witness
Not checked — no run on this page records step 7 passing for it.
1aa8a1c1b9f3.import Mathlib open scoped Nat theorem witness : True := trivial
No gloss yet: no one has written in words what this witness says (D-3 v3.30); the Lean above is the witness. How to write one →
Attempts (2)
2 recorded. Routes refuted: none. Failure classes: route-dead-ends 1.
Untrusted contributor text — a partial assembly: it records an attempt, not a proof; its attestation names the file, and no hash in the record binds these bytes.
Untrusted: partial assembly (D-12 #5), by t1015c-a09; merged in 7a4aeb081a83 under attestations/000544.json, whose step 2 took this file as a partial. A partial records an attempt, not a proof: the gate replayed it with its holes left as sorry. Rendered from targets/erdos-1094/nodes/erdos-1094--h3--h1--h1--h2--h1/attempts/20261015T145026Z-t1015c-a09-partial.lean.
Untrusted contributor text — an outline the gate extracted from this partial assembly; its holes are sorry steps, and it records an attempt, not a proof.
Outline of 20261015T145026Z-t1015c-a09-partial.lean, extracted by the gate at fa0a13ba270d from the proof’s elaboration: each step is a claim the proof establishes and the goal it leaves. Open a step for what it uses and its Lean lines.
h_k3onehole∃ (K : ℕ), ∀ (n k : ℕ), K < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → k % (3 : ℕ) = (1 : ℕ) → (1 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % pholeLeaves
∃ (K₃ : ℕ), ∀ (n k : ℕ), K₃ < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → (0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withh_k3one : ∃ (K : ℕ), ∀ (n k : ℕ), K < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → k % (3 : ℕ) = (1 : ℕ) → (1 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p.Uses library
Nat.PrimeNat.Prime pmeans thatpis a prime number, that is, a natural number at least 2 whose only divisors arepand1. .Left open as a hole; its statement is erdos-1094--h3--h1--h1--h2--h1--h1 (open).
Lean, lines 21–32
have h_k3one : ∃ (K : ℕ), ∀ (n k : ℕ), K < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → k % (3 : ℕ) = (1 : ℕ) → (1 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := sorryh_k3twohole∃ (K : ℕ), ∀ (n k : ℕ), K < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → k % (3 : ℕ) = (2 : ℕ) → n % (3 : ℕ) = (2 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % pholeLeaves
∃ (K₃ : ℕ), ∀ (n k : ℕ), K₃ < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → (0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withh_k3two : ∃ (K : ℕ), ∀ (n k : ℕ), K < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → k % (3 : ℕ) = (2 : ℕ) → n % (3 : ℕ) = (2 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p.Uses library
Nat.PrimeNat.Prime pmeans thatpis a prime number, that is, a natural number at least 2 whose only divisors arepand1. .Left open as a hole; its statement is erdos-1094--h3--h1--h1--h2--h1--h2 (open).
Lean, lines 33–44
have h_k3two : ∃ (K : ℕ), ∀ (n k : ℕ), K < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → k % (3 : ℕ) = (2 : ℕ) → n % (3 : ℕ) = (2 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := sorrys3obtain∃ (K : ℕ), ∀ (n k : ℕ), K < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → k % (3 : ℕ) = (1 : ℕ) → (1 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % pLeaves
∃ (K₃ : ℕ), ∀ (n k : ℕ), K₃ < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → (0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withA : ℕ,hA : ∀ (n k : ℕ), A < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → k % (3 : ℕ) = (1 : ℕ) → (1 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p.Lean, line 45
obtain ⟨A, hA⟩ := h_k3one
s4obtain∃ (K : ℕ), ∀ (n k : ℕ), K < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → k % (3 : ℕ) = (2 : ℕ) → n % (3 : ℕ) = (2 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % pLeaves
∃ (K₃ : ℕ), ∀ (n k : ℕ), K₃ < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → (0 : ℕ) < k % (3 : ℕ) → k % (3 : ℕ) ≤ n % (3 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withB : ℕ,hB : ∀ (n k : ℕ), B < k → (2 : ℕ) * k ≤ n → n < k * k → k % (2 : ℕ) = (0 : ℕ) → k % (3 : ℕ) = (2 : ℕ) → n % (3 : ℕ) = (2 : ℕ) → k % (5 : ℕ) ≤ n % (5 : ℕ) → k % (7 : ℕ) ≤ n % (7 : ℕ) → k % (11 : ℕ) ≤ n % (11 : ℕ) → k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p.Lean, line 46
obtain ⟨B, hB⟩ := h_k3two
hAkhaveA < kLeaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withhAk : A < k.Uses library
lt_of_le_of_lt,le_max_left.Lean, line 49
have hAk : A < k := lt_of_le_of_lt (le_max_left A B) hk
hBkhaveB < kLeaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withhBk : B < k.Uses library
lt_of_le_of_lt,le_max_right.Lean, line 50
have hBk : B < k := lt_of_le_of_lt (le_max_right A B) hk
hk3havek % (3 : ℕ) < (3 : ℕ)Leaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withhk3 : k % (3 : ℕ) < (3 : ℕ).Uses library
Nat.mod_lt.Lean, line 51
have hk3 : k % 3 < 3 := Nat.mod_lt _ (by norm_num)
hn3haven % (3 : ℕ) < (3 : ℕ)Leaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withhn3 : n % (3 : ℕ) < (3 : ℕ).Uses library
Nat.mod_lt.Lean, line 52
have hn3 : n % 3 < 3 := Nat.mod_lt _ (by norm_num)
s9caseLeaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withh : k % (3 : ℕ) = (1 : ℕ).Lean, line 54
· exact hA n k hAk h1 h2 h3 h (by omega) h6 h7 h8 h9
s10caseLeaves
∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p, withh : k % (3 : ℕ) = (2 : ℕ).Lean, line 55
· exact hB n k hBk h1 h2 h3 h (by omega) h6 h7 h8 h9
import Mathlib
import Nodes.«erdos-1094--h3--h1--h1--h2--h1».Context
open scoped Nat
/-! Hole `h_p5to13` of a merged partial proof, as a node (D-12 #5, D-29).
Statement generated by the gate from the assembly; immutable (D-3). -/
theorem erdos_1094__h3__h1__h1__h2__h1 : ∃ (K₃ : ℕ),
∀ (n k : ℕ),
K₃ < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
(0 : ℕ) < k % (3 : ℕ) →
k % (3 : ℕ) ≤ n % (3 : ℕ) →
k % (5 : ℕ) ≤ n % (5 : ℕ) →
k % (7 : ℕ) ≤ n % (7 : ℕ) →
k % (11 : ℕ) ≤ n % (11 : ℕ) →
k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := by
have h_k3one : ∃ (K : ℕ),
∀ (n k : ℕ),
K < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
k % (3 : ℕ) = (1 : ℕ) →
(1 : ℕ) ≤ n % (3 : ℕ) →
k % (5 : ℕ) ≤ n % (5 : ℕ) →
k % (7 : ℕ) ≤ n % (7 : ℕ) →
k % (11 : ℕ) ≤ n % (11 : ℕ) →
k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := sorry
have h_k3two : ∃ (K : ℕ),
∀ (n k : ℕ),
K < k →
(2 : ℕ) * k ≤ n →
n < k * k →
k % (2 : ℕ) = (0 : ℕ) →
k % (3 : ℕ) = (2 : ℕ) →
n % (3 : ℕ) = (2 : ℕ) →
k % (5 : ℕ) ≤ n % (5 : ℕ) →
k % (7 : ℕ) ≤ n % (7 : ℕ) →
k % (11 : ℕ) ≤ n % (11 : ℕ) →
k % (13 : ℕ) ≤ n % (13 : ℕ) → ∃ (p : ℕ), Nat.Prime p ∧ p ≤ k ∧ n % p < k % p := sorry
obtain ⟨A, hA⟩ := h_k3one
obtain ⟨B, hB⟩ := h_k3two
refine ⟨max A B, ?_⟩
intro n k hk h1 h2 h3 h4 h5 h6 h7 h8 h9
have hAk : A < k := lt_of_le_of_lt (le_max_left A B) hk
have hBk : B < k := lt_of_le_of_lt (le_max_right A B) hk
have hk3 : k % 3 < 3 := Nat.mod_lt _ (by norm_num)
have hn3 : n % 3 < 3 := Nat.mod_lt _ (by norm_num)
rcases (by omega : k % 3 = 1 ∨ k % 3 = 2) with h | h
· exact hA n k hAk h1 h2 h3 h (by omega) h6 h7 h8 h9
· exact hB n k hBk h1 h2 h3 h (by omega) h6 h7 h8 h9How to read this page
No explainer yet. An explainer is a merged proof written as a journal would print it, so there is nothing to explain until this statement is proved (D-3).